Equality begins at one source point
If tangents from P touch at A and B, then PA=PB. The shared external point controls the equality.
If tangents from P touch at A and B, then PA=PB. The shared external point controls the equality.
OA is perpendicular to PA, OB to PB, OA=OB and OP is common; these facts prepare RHS congruence.
Triangles OAP and OBP are right triangles, OA=OB and OP is common. RHS congruence gives PA=PB by CPCT.
If PA=2x+3 and PB=5x-12, equate them because both start at P; x=5 and each length is 13.
Colour-code each source point, equate only its tangent pair, then solve the length or perimeter equation.
Use congruent triangles to establish equal half-angles, then combine them with the two contact right angles in quadrilateral OAPB.
List equal tangent pairs vertex by vertex, rewrite each side as two pieces, and derive the required perimeter or opposite-side relation.
Combine perpendicular radii, RHS congruence, equal tangents, angle sum and algebra; write the reason beside each equality.
Progress from stating equality, through its RHS proof, to equations, angles and circumscribed figures; match reasoning depth to marks.
Prove equal tangents, solve a tangent equation, determine an angle and complete a polygon relation with reasons.