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Solving Quadratic Equations by Factorisation

Learning goals

Concept lesson

From factors to roots

A root makes the quadratic equation true. Factorisation exposes the values that make one factor zero.

Product ac and sum b

For ax^2+bx+c, seek two numbers whose product is ac and sum is b; split bx, group and factor.

Zero-product rule and root signs

If AB=0, then A=0 or B=0. Thus x-r=0 gives x=r, while x+r=0 gives x=-r.

Split and factorise

For 2x^2-5x+3=0, ac=6 and the pair -2,-3 sums to -5. Write 2x^2-2x-3x+3=0 and factor (2x-3)(x-1)=0.

Apply both factor equations

2x-3=0 gives x=3/2, and x-1=0 gives x=1. State both roots.

Read roots from factors

Write both roots of (x-4)(3x+2)=0. The scaffold requires each factor equation before its root.

Verify both roots

Substitute every found root into the original unfactorised equation. A non-zero result signals a factor or sign error.

Repair an incorrect factorisation

A student writes x^2+8x+12=(x+2)(x+4). Expand the proposed factors, locate the mismatch and repair the factorisation.

Two-mark factorisation answer

Show the split, grouping, two linear factors, zero-product step and both roots. Do not jump from the original equation to answers.

Exit ticket

Find the roots of 3x^2-7x+2=0 by factorisation and verify both roots in the original equation.